There. You happy? This should help you divide 200 cm (2 metres, the width of the middle part) by the number of letters in Rindfleischetikettierungsüberwachungsaufgabenübertragungsgesetz.
The midde part actually has to be wider than 200cm, since there has to be a slot between the two wings while they aren’t “stretched”. I guess 200.5cm. So 200.5/63 = 3.18253968254 which is close to π. Interesting. πcm = 200.5cm/63 letters. Which means one letter in general is πcm. Based on that, we can say 1 meter is round about 31.8309886184 letters.
there has to be a slot between the two wings while they aren’t “streched”
Uh. Um. Your mum has to have a slot.
I don’t understand what you’re saying because I’m not a NERRRRRD* and you’re AGAIN questioning my primary school teacher and you’re using a lot of numbers like a NERRRRD so I shall disregard any further comments concerning the topic of the width and height of German blackboards.
Sorry, there was an
at the wrong place.
I’m taking it completely serious, do you?
There. You happy? This should help you divide 200 cm (2 metres, the width of the middle part) by the number of letters in Rindfleischetikettierungsüberwachungsaufgabenübertragungsgesetz.
The midde part actually has to be wider than 200cm, since there has to be a slot between the two wings while they aren’t “stretched”. I guess 200.5cm. So 200.5/63 = 3.18253968254 which is close to π. Interesting. πcm = 200.5cm/63 letters. Which means one letter in general is πcm. Based on that, we can say 1 meter is round about 31.8309886184 letters.
E: Another E
Uh. Um. Your mum has to have a slot.
I don’t understand what you’re saying because I’m not a NERRRRRD* and you’re AGAIN questioning my primary school teacher and you’re using a lot of numbers like a NERRRRD so I shall disregard any further comments concerning the topic of the width and height of German blackboards.
*
* of that type
So which TYYYYPPO of NERRRRD are you then?